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memory: expose alignment used for allocating RAM as MemoryRegion API

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introduce memory_region_get_alignment() that returns
underlying memory block alignment or 0 if it's not
relevant/implemented for backend.

Signed-off-by: Igor Mammedov <imammedo@redhat.com>
Reviewed-by: Michael S. Tsirkin <mst@redhat.com>
Signed-off-by: Michael S. Tsirkin <mst@redhat.com>
This commit is contained in:
Igor Mammedov
2014-10-31 16:38:37 +00:00
committed by Michael S. Tsirkin
parent 92a37a04d6
commit a2b257d621
8 changed files with 22 additions and 8 deletions
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3
include/qemu/osdep.h
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@ -5,6 +5,7 @@
#include <stdarg.h>
#include <stddef.h>
#include <stdbool.h>
#include <stdint.h>
#include <sys/types.h>
#ifdef __OpenBSD__
#include <sys/signal.h>
@ -103,7 +104,7 @@ typedef signed int int_fast16_t;
int qemu_daemon(int nochdir, int noclose);
void *qemu_try_memalign(size_t alignment, size_t size);
void *qemu_memalign(size_t alignment, size_t size);
void *qemu_anon_ram_alloc(size_t size);
void *qemu_anon_ram_alloc(size_t size, uint64_t *align);
void qemu_vfree(void *ptr);
void qemu_anon_ram_free(void *ptr, size_t size);